Thursday, January 12, 2012

Frictional force complicated queston !!?

a happy fellow is pulling two ducks on wheels around his room. The ducks are 2.0 kg and 5.0 kg(front duck) and the guy is pulling them with a force of 10N

a) calculate the new acceleration if 碌 is 0.10

b) calculate the tension in the rope between the ducksFrictional force complicated queston !!?
a. m1*g*碌+m2*g*碌 = F(reverse)



[F(forward)-F(reverse)]/(m1+m2)=accele鈥?br>


b.simple

tension in string everywhere = 10N

1 comment:

  1. Good Post, I am a big believer in posting comments on sites to let the blog writers know that they’ve added something advantageous to the world wide web! happy wheels

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